![]() So this shows al four angles are 60 degrees, which means not only is it a scalene triangle, but an equilateral triangle. One angle is 60 and the other two are some other angle x where all three equal 180. ![]() ![]() so in other words use some algebra to find the two other angles. Also, you should know the angles of a triangle add up to 180. Since it is a scalene triangle you know the measure of the other two angles are the same. this means each triangle will have an angle of measure 360/n, where n is the number of sides. Basically each side will have one of these. You want to count how many of these triangles you can make. You know both radii are 8 cm, which means you have an isosceles triangle. it is also important to know the apothem This works for any regular polygon.Ĭhoose a side and form a triangle with the two radii that are at either corner of said side. We modify our function to draw many lines as the last hexagon fits in the canvas height.Radius is the distance from the center to a corner. The rest is going to be the same taking into account this offset. However, depending how many hexagons can fit in a row, we have to add rsin60º if is odd or 2rsin60º if is even. From the center (0,0) we can see that the blue arrow takes a distance of twice the length of the hexagon height that sums up to 2rsin60º. This would be the final scheme of our grid, showing the first four centers of each row to get a good view on what is going on. But, how much lower is it from the original row? Let's find it out: All we need is to repeat the same procedure but in the row below repeatedly. That is it! We are just one step away from success. Notice whether the subsequent hexagon, in every iteration, that we are going to draw fits inside the canvas.
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